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प्रश्न
Why does the element carbon from a large number of carbon compounds?
उत्तर
The element, carbon, forms a large number of carbon compounds because of its property of self combination (catenation). The ability of one carbon atom to combine with the many other carbon atoms to form long chains produces a large number of carbon compounds. This long chain of carbon atoms supports the other atoms to get attached to it in a number of ways due to which a large number of carbon compounds are obtained.
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संबंधित प्रश्न
Which of the following is the molecular formula of benzene?
C6H6, C6H10, C6H12, C6H14
Give the name and structural formula of one member each of the following:
alkyne
Write the molecular formula and structure of benzene.
Write the molecular formula and structure of cyclohexane. How many covalent bonds are there in a molecule of cyclohexane?
The number of carbon atoms in the organic compound named as 2,2-dimethylpropane is:
(a) two
(b) five
(c) three
(d) four
The solid element A exhibits the property of catenation. It is also present in the form of a gas B in the air which is utilised by plants in photosynthesis. An allotrope C of this element is used in glass cutters.
(a) What is element A?
(b) What is the gas B?
(c) Name the allotrope C.
(d) State another use of allotrope C (other than in glass cutters).
(e) Name another allotrope of element A which exists as spherical molecules.
(f) Name a yet another allotrope of element A which conduct electricity.
You are given the following molecular formulae of some hydrocarbons:
C5H8; C7H14; C6H6; C5H10; C7H12; C6H12
Which formula represent cyclohexane as well as hexene?
A reagent which can help us to distinguish between alkenes and alkynes is ______.
Which of the following are correct structural isomers of butane?
- \[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{..}\\
|\phantom{....}|\phantom{....}|\phantom{....}|\phantom{..}\\
\ce{H - C - C - C - C - H}\\
|\phantom{....}|\phantom{....}|\phantom{....}|\phantom{..}\\
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{..}
\end{array}\] - \[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\phantom{....}|\\
\ce{H - C - C - C - H}\\
|\phantom{.....}\backslash\phantom{..}|\\
\phantom{.....}\ce{H}\phantom{.......}\ce{C - H}\\
\phantom{.........}|\\
\phantom{.........}\ce{H}
\end{array}\] - \[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\phantom{....}|\\
\ce{H - C - C - C - H}\\
|\phantom{....}\phantom{....}|\\
\ce{H}\phantom{........}\ce{H}\\
|\\
\ce{H - C - H}\\
|\\\ce{H}
\end{array}\] - \[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\\
\ce{H - C - C - H}\\
|\phantom{....}|\\
\ce{H - C - C - H}\\
|\phantom{....}|\\
\ce{H}\phantom{...}\ce{H}
\end{array}\]
Match the reactions given in Column (A) with the names given in column (B).
| Column (A) | Column (B) | ||
(a) |
`"CH"_3"OH" + "CH"_3"COOH"overset("H"^+)(->) "CH"_3"COOCH"_3 + "H"_2"O"` | (i) | Addition reaction |
| (b) | `"CH"_3 = "CH"_2 + "H"_2 overset("Ni")(->)"CH"_3 - "CH"_3` | (ii) | Substitution reaction |
| (c) | `"CH"_4 + "Cl"_2overset("Sunlight")(->)"CH"_3"Cl" + "HCl"` | (iii) | Neutralisation reaction |
| (d) | `"CH"_3"COOH" + "NaOH" -> "CH"_3"COONa" + "H"_2"O"` | (iv) | Esterification reaction |
