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प्रश्न
Write a short note.
Catenation power
उत्तर
- The unique property of carbon atom to form covalent bonds with other carbon atoms giving rise to extremely big molecules is called catenation power.
- The covalent bond between two carbon atoms is strong and stable.
- This is the reason carbon is bestowed with catenation power.
- Due to catenation power, carbon can form a large number of compounds containing open chains or closed chains of carbon atoms.
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संबंधित प्रश्न
Explain the following term with an example.
Functional group
Define Hydrocarbons.
Find the odd one out and give its explanation.
Find the odd one out and give its explanation.
Find the odd one out and give its explanation.
Write the molecular formula of the given compound.
Ethyl ethanoate
Write the molecular formula of the given compound.
Ethyl alcohol
Write the molecular formula of the given compound.
Isobutane
Carbon compounds contain only open chains of carbon atoms.
Benzene is a cyclic unsaturated hydrocarbon.
Cyclohexane is a branched chain type of hydrocarbon.
In LPG, butane is a flammable component.
Distinguish between:
Open chain hydrocarbons - Closed chain hydrocarbons
Distinguish between:
Alkane - Alkene
Complete the given chart with writing the correct functional group of carbon compounds.
(Ester, Aldehyde, Ketone, Carboxylic acid, Alcohol, Ether)
| -O-H | |
| \[\begin{array}{cc} \ce{O}\phantom{..}\\ ||\phantom{..}\\ \ce{-C-H} \end{array}\] |
|
| \[\begin{array}{cc} \ce{O}\\ ||\\ \ce{-C-} \end{array}\] |
|
| \[\begin{array}{cc} \ce{O}\phantom{.....}\\ ||\phantom{.....}\\ \ce{-C-O-H} \end{array}\] |
|
| -O- | |
| \[\begin{array}{cc} \ce{O}\phantom{..}\\ ||\phantom{..}\\ \ce{-C-O} \end{array}\] |
|
|
\[\begin{array}{cc} |
Which of these is true for most of the organic compounds?
Which of the following is not a straight chain hydrocarbon?
Consider the following organic compounds:
| (i) \[\begin{array}{cc} \ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\ |\phantom{....}|\phantom{....}|\\ \ce{H - C - C - C = O}\\ |\phantom{....}|\phantom{.....}\\ \ce{H}\phantom{....}\ce{H}\phantom{.....} \end{array}\] |
(ii) \[\begin{array}{cc} \phantom{....}\ce{H}\phantom{...}\ce{H}\phantom{....}\\ \phantom{....}|\phantom{....}|\phantom{....}\\ \ce{H - C - C = O}\\|\phantom{.....}\\ \ce{H}\phantom{.....}\end{array}\] |
- Name the functional group present in these compounds.
- Write the general formula for the compounds of this functional group.
- State the relationship between these compounds and draw the structure of any other compound having a similar functional group.
Identify heteroatom (s) in the following compound.
\[\begin{array}{cc}
\ce{CH3CH2 - C - CH3}\\\
\phantom{....}||\
\ce\\\phantom{....}{O}\end{array}\]
______ is the functional group of carboxylic acid.
