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प्रश्न
Write balanced chemical equation to show :
The dehydrating property of conc.sulphuric acid
उत्तर
\[\ce{C12H22O11 ->[H2SO4] 12C + 11H2O}\]
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संबंधित प्रश्न
Write a balanced chemical equation for the following:
Action of concentrated sulphuric acid on Sulphur.
How will you distinguish between dilute hydrochloric acid and dilute sulphuric acid using lead nitrate solution?
A, B, C, and D summarize the properties of sulphuric acid depending on whether it is dilute or concentrated.
A = Typical acid property
B = Non volatile acid
C = Oxidizing agent
D = Dehydrating agent
Choose the property (A, B, C or D) depending on which is relevant to each of the following
1) Preparation of Hydrogen chloride gas
2) Preparation of Copper sulphate from copper oxide.
3) An action of conc. Sulphuric acid on Sulphur.
Give one equation to show the following properties of sulphuric acid:
Acidic nature
Name the products formed when hot and concentrated sulphuric acid reacts with NaOH.
Name the following:
Products obtained by treating ferrous sulphide with dilute sulphuric acid.
Choose the current answer from the options given below :
When conc. H2SO4 comes in contact with sugar, it becomes black due to
The following statement is correct only under certain conditions. Rewrite the statement including the appropriate conditions.
Oxalic acid reacts with sulphuric acid to produce carbon monoxide and carbon dioxide.
- Name the catalyst which helps in the conversion of sulphur dioxide to sulphur trioxide in step C.
- In the contact process for the manufacture of sulphuric acid, sulphur trioxide is not converted to sulphuric acid by reacting it with water. Instead a two-step procedure is used. Write the equations for the two steps involved in D.
- What type of substance will liberate sulphur dioxide from sodium sulphite in step E?
- Write the equation for the reaction by which sulphur dioxide is converted to sodium sulphite in step F.
Which property of sulphuric acid accounts for its use as a dehydrating agent ?
