Advertisements
Advertisements
प्रश्न
Write the next term of the AP `sqrt(2) , sqrt(8) , sqrt(18),.........`
उत्तर
The given AP is `sqrt(2) , sqrt(8) , sqrt(18) ,................`
On simplifying the terms, we get:
`sqrt (2) , 2 sqrt(2) , 3 sqrt(2) ,..................`
`Here , a= sqrt(2) and d = ( 2 sqrt(2) - sqrt(2)) = sqrt(2)`
∴ Next term `T_4 = a + 3d = sqrt(2) + 3 sqrt(2) = 4 sqrt(2) = sqrt(32)`
APPEARS IN
संबंधित प्रश्न
The first and the last terms of an AP are 7 and 49 respectively. If sum of all its terms is 420, find its common difference.
How many terms of the AP. 9, 17, 25 … must be taken to give a sum of 636?
Find the value of x for which (x + 2), 2x, ()2x + 3) are three consecutive terms of an AP.
The first term of an AP is p and its common difference is q. Find its 10th term.
Find the sum \[7 + 10\frac{1}{2} + 14 + . . . + 84\]
Write the value of a30 − a10 for the A.P. 4, 9, 14, 19, ....
Q.5
Q.13
Find the sum of those integers between 1 and 500 which are multiples of 2 as well as of 5.
Find the sum of those integers from 1 to 500 which are multiples of 2 as well as of 5.