Advertisements
Advertisements
प्रश्न
Write the complement angle of: `1/5` of 160°
उत्तर
Complement angle of `1/5` of 160°
= 90° - `(1/5 xx 160^circ)`
= 90° - 32°
= 58°
APPEARS IN
संबंधित प्रश्न
In the given diagram, ABC is a straight line. If y =`1 1/2` right angles; find x.
In the given figure:
(i) If ∠AOB = 45°, ∠BOC = 30° and ∠AOD= 110°; find : angles COD and BOD.
(ii) If ∠BOC = ∠DOC = 34° and ∠AOD = 120° ; find : angle AOB and angle AOC.
(iii) If ∠AOB = ∠BOC = ∠COD = 38° find : reflex angle AOC and reflex angle AOD.
Write the complement angle of: (x – 10)°
Write the supplement angle of: 49°
Write the complement angle of: `1/6` of 90°
60% of 100°
`3/4` of 160°
Two complementary angles are in the ratio 7 : 8. Find the angles.
The measures of two complementary angles are (2x – 7)° and (x + 4)°. Find x.
Find the angle that is three times its complementary angle.
