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प्रश्न
Write the equation for the reaction taking place between 1, 2-dibromoethane, and alcoholic potassium hydroxide.
उत्तर
\[\begin{array}{cc}
\ce{CH2 - CH2 + 2KOH -> 2KBr + \underset{Acetylene}{CH ≡ CH} + 2H2O}\\
|\phantom{......}|\phantom{...........................................}\\
\ce{\underset{1, 2-dibromoethane}{Br\phantom{....}Br}}\phantom{..........................................}\\
\end{array}\]
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