Advertisements
Advertisements
प्रश्न
Write the first three terms of the APs when a and d are as given below:
a = `1/2`, d = `-1/6`
उत्तर
Given that,
First term (a) = `1/2`
and common difference (d) = `-1/6`
∵ nth term of an AP,
Tn = a + (n – 1)d
∴ Second term of an AP,
T2 = a + d
= `1/2 - 1/6`
= `2/6`
= `1/3`
and third term of an AP,
T3 = a + 2d
= `1/2 - 2/6`
= `1/2 - 1/3`
= `(3 - 2)/6`
= `1/6`
Hence, required three terms are `1/2, 1/3, 1/6`.
APPEARS IN
संबंधित प्रश्न
In the following APs, find the missing term in the boxes:
`-4, square, square, square, square, 6`
The 17th term of an AP exceeds its 10th term by 7. Find the common difference.
Which term of the A.P. 3, 15, 27, 39, ... will be 120 more than its 21st term?
A child puts one five-rupee coin of her saving in the piggy bank on the first day. She increases her saving by one five-rupee coin daily. If the piggy bank can hold 190 coins of five rupees in all, find the number of days she can continue to put the five-rupee coins into it and find the total money she saved.
Write your views on the habit of saving.
If Sn.., the sum of first n terms of an AP is given by Sn =3n2- 4n, find the nth term.
The nth term of an A.P. 5, 2, -1, -4, -7 … is ______.
The 10th term from the end of the A.P. -5, -10, -15,…, -1000 is ______.
The first four terms of an AP, whose first term is –2 and the common difference is –2, are ______.
What is the common difference of an AP in which a18 – a14 = 32?
Find the common difference of an A.P. whose nth term is given by an = 6n – 5.