Question

Write two equations for which 2 is the solution.

Answer 1

Let the two numbers be x and y, which has solution 2 in equation.

(i) For getting first equation, the number x is multiplied by 2, then the number is 2x.

After that, 3 is subtracted from it which result into 1.

Hence, `2x - 3` = 1

`2x` = 3 + 1   .....[Transposing – 3 to RHS]

⇒ `2x` = 4

⇒ `(2x)/2 = 4/2`  ......[Dividing both sides by 2]

⇒ `x` = 2

(ii) For getting second equation, the number y is multiplied by 3, then the number is 3y.

After that, it will be added to 4 which result into 10.

Hence, 3y + 4 = 10

On solving, 3y = 10 – 4

⇒ 3y = 6   .....[Transposing + 4 to RHS]

⇒ `(3y)/3 = 6/3`  ......[Dividing both sides by 3]

⇒ y = 2

Hence, two equations are 2x – 3 = 1 and 3y + 4 = 10.