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प्रश्न
Write two equations for which 2 is the solution.
उत्तर
Let the two numbers be x and y, which has solution 2 in equation.
(i) For getting first equation, the number x is multiplied by 2, then the number is 2x.
After that, 3 is subtracted from it which result into 1.
Hence, `2x - 3` = 1
`2x` = 3 + 1 .....[Transposing – 3 to RHS]
⇒ `2x` = 4
⇒ `(2x)/2 = 4/2` ......[Dividing both sides by 2]
⇒ `x` = 2
(ii) For getting second equation, the number y is multiplied by 3, then the number is 3y.
After that, it will be added to 4 which result into 10.
Hence, 3y + 4 = 10
On solving, 3y = 10 – 4
⇒ 3y = 6 .....[Transposing + 4 to RHS]
⇒ `(3y)/3 = 6/3` ......[Dividing both sides by 3]
⇒ y = 2
Hence, two equations are 2x – 3 = 1 and 3y + 4 = 10.
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(i) The number of corners of a quadrilateral | (A) = |
(ii) The variable in the equation 2p + 3 = 5 | (B) constant |
(iii) The solution of the equation x + 2 = 3 | (C) +1 |
(iv) solution of the equation 2p + 3 = 5 | (D) –1 |
(v) A sign used in an equation | (E) p |
(F) x |