हिंदी

X→LiAlHX4 in etherY→CX2HX5BrZ⟶Triethylamine X and Z are ____________ respectively. -

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प्रश्न

\[\ce{X ->[LiAlH4 in ether] Y ->[C2H5Br] Z -> Triethylamine}\]

X and Z are ____________ respectively.

विकल्प

  • nitromethane and dimethylamine

  • nitroethane and diethylamine

  • ethyl cyanide and diethylamine

  • 1-nitropropane and ethylamine

MCQ
रिक्त स्थान भरें

उत्तर

\[\ce{X ->[LiAlH4 in ether] Y ->[C2H5Br] Z -> Triethylamine}\]

X and Z are nitroethane and diethylamine respectively.

Explanation:

\[\ce{\underset{\underset{(X)}{Nitroethane}}{C2H5 - NO2} ->[LiAlH4 in ether] \underset{\underset{(Y)}{Ethylamine}}{C2H5 - NH2} ->[C2H5Br] \underset{\underset{(Z)}{Diethyl amine}}{(C2H5)2NH} ->[C2H5Br] \underset{Triethyl amine}{(C2H5)3N}}\]

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