Question

\[\ce{X ->[LiAlH4 in ether] Y ->[C2H5Br] Z -> Triethylamine}\]

X and Z are ____________ respectively.

Options

• nitromethane and dimethylamine

• nitroethane and diethylamine

• ethyl cyanide and diethylamine

• 1-nitropropane and ethylamine

Answer 1

\[\ce{X ->[LiAlH4 in ether] Y ->[C2H5Br] Z -> Triethylamine}\]

X and Z are nitroethane and diethylamine respectively.

Explanation:

\[\ce{\underset{\underset{(X)}{Nitroethane}}{C2H5 - NO2} ->[LiAlH4 in ether] \underset{\underset{(Y)}{Ethylamine}}{C2H5 - NH2} ->[C2H5Br] \underset{\underset{(Z)}{Diethyl amine}}{(C2H5)2NH} ->[C2H5Br] \underset{Triethyl amine}{(C2H5)3N}}\]