Advertisements
Advertisements
प्रश्न
100 g of ice at -10°C is heated. It is converted into steam. Calculate the quantity of heat which it has consumed. (Sp. heat of ice = 2100J/kg°C, sp. heat of water= 4200 J/kgK, sp. heat of water = 42000 J/kgK, sp. latent heat of ice = 2260000 J/kg).
उत्तर
Amount of heat required to oonvert ice into steam is as given below:
(ice from -10°C to 0°C) = 0.1 x 2100 x 10 = 2100 J
(ice at 0°C to water at 0°C) = 0.1 x 336000 = 33600 J
(water from 0°C to 100°C) = 0.1 x 4200 x 100 = 42000 J
(water at 100°C to steam at 100°C) = 0.1 x 2260000 = 226000 J
Total amount of heat required = 2100 + 33600 + 42000 + 226000 = 30370 J
APPEARS IN
संबंधित प्रश्न
How can a temperature in degree Celsius be converted into S.I. unit of temperature?
Define calorimetry ?
Explain the terms melting ?
What mass of ice at 0°C will be required to cool 0.9 kg of water from 35°C to 0°C? Assume all the ice used melts. The specific heat capacity of water is 4.2 x 103 J/kgoC and specific latent heat of fusion of ice is 336 x 103 J/kg.
Fill in the following blank using suitable word:
Evaporation causes ..........
Name the material of which it is made of. Give two reasons for using the material stated by you.
1 kg of ice at 0o is heated at constant rate and its temperature is recorded after every 30 s till steam is formed at 100o C. Draw a temperature time graph to represent the change of phase.
With the help of a neat diagram, explain the working of a calorimeter.
