मराठी

1500 families with 2 children were selected randomly and the following data were recorded: - Mathematics

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प्रश्न

1500 families with 2 children were selected randomly and the following data were recorded:

Number of girls in a family 0 1 2
Number of families 211 814 475

 

If a family is chosen at random, compute the probability that it has:
(i) No girl
(ii) 1 girl
(iii) 2 girls
(iv) at most one girl
(v) more girls than boys
थोडक्यात उत्तर

उत्तर

The total number of trials is 1500.

Remember the empirical or experimental or observed frequency approach to probability.

If n be the total number of trials of an experiment and A is an event associated to it such that A happens in m-trials. Then the empirical probability of happening of event is denoted by p(A) and is given by

P(A) = `m/n`

(i) Let be the event of having no girl.

The number of times A happens is 211.

Therefore, we have

P(A) = `211/1500`

=0.1406

(ii) Let B be the event of having one girl.

The number of times B happens is 814.

Therefore, we have

P(B) = `814/1500`

=0.5426

(iii) Let C be the event of having two girls.

The number of times C happens is 475.

Therefore, we have

P(C) = `475/1500`

=0.3166

(iv) Let D be the event of having at most one girl.

The number of times D happens is 211+814=1025.

Therefore, we have

P(D) = `1025/1500`

=0.6833

(v) Let be the event of having more girls than boys.

The number of times E happens is 475.

Therefore, we have

P(E) = `475/1500`

=0.3166

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पाठ 25: Probability - Exercise 25.1 [पृष्ठ १३]

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आरडी शर्मा Mathematics [English] Class 9
पाठ 25 Probability
Exercise 25.1 | Q 4 | पृष्ठ १३

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