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प्रश्न
1.56 g of sodium peroxide reacts with water according to the following equation:
\[\ce{2Na2O2 + 2H2O -> 4NaOH + O2}\]
Calculate the mass of oxygen liberated.
उत्तर
156 g of Na2O2 liberates O2 = 32 g
∴ 1.56 g of Na2O2 liberates O2
= `32/156 xx 1.56`
= 0.32 g
संबंधित प्रश्न
Differentiate between 2H and H2
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\[\ce{2KCI3 ->[MnO2] 2KCl + 3O2}\]
- Calculate the mass of KClO3 required to produce 6.72 litres of O2 at STP. [atomic masses of K = 39, Cl = 35.5, O = 16].
- Calculate the number of moles of oxygen present in the above volume and also the number of molecules.
- Calculate the volume occupied by 0.01 mole of CO2 at STP.
How much calcium oxide is formed when 82g of calcium nitrate is heated? Also find the volume of nitrogen dioxide evolved:
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The ratio between the number of molecules in 2g of hydrogen and 32 g of oxygen is
[Given that H=1,O=16]
200 cm3 of hydrogen and 150 cm3 of oxygen are mixed and ignited, as per the following reaction,
\[\ce{2H2 + O2 → 2H2O}\]
What volume of oxygen remains unreacted?
1.56 g of sodium peroxide reacts with water according to the following equation:
\[\ce{2Na2O2 + 2H2O -> 4NaOH + O2}\]
Calculate the mass of sodium hydroxide formed.
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\[\ce{(NH4)2Cr2O7 -> N2 + Cr2O3 + 4H2O}\]
If 63 g of ammonium dichromate decomposes. Calculate the volume of N2 evolved at STP.
Solid ammonium dichromate decomposes as:
\[\ce{(NH4)2Cr2O7 -> N2 + Cr2O3 + 4H2O}\]
If 63 g of ammonium dichromate decomposes. Calculate what will be the loss of mass.
1.56 g of sodium peroxide reacts with water according to the following equation:
\[\ce{2Na2O2 + 2H2O -> 4NaOH + O2}\]
Calculate the volume of oxygen liberated at STP.
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\[\ce{Al4C3 + 12H2O -> 3CH4 + 4Al(OH)3}\]
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