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प्रश्न
[2–1 + 3–1 + 4–1]0 = ______.
उत्तर
[2–1 + 3–1 + 4–1]0 = 1.
Explanation:
Using law of exponents, a0 = 1 ...[∵ A is non-zero integer]
∴ [2–1 + 3–1 + 4–1]0 = 1
Hence, [2–1 + 3–1 + 4–1]0 = 1
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