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प्रश्न
200 g of of ice at 0°C is added to 2 kg of water at 30°C. What is the temperature of the mixture?
संख्यात्मक
उत्तर
Let the final temperature of the mixture be t.
Heat gained by ice = Heat lost by water
m1L + m1 x C x (t - 0) = mz x C x (30 - t)
(200 x 336) + (200 x 4.2 x t) = 2000 x 4.2 x (30 - t)
336 + 4.2t = 42 (30 - t)
t = 20°C
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