Question

200 g of of ice at 0°C is added to 2 kg of water at 30°C. What is the temperature of the mixture?

Answer 1

Let the final temperature of the mixture be t.

Heat gained by ice = Heat lost by water

m1L + m₁ x C x (t - 0) = m_z x C x (30 -  t)

(200 x 336) + (200 x 4.2 x t) = 2000 x 4.2 x (30 - t)

336 + 4.2t = 42 (30 - t)

t = 20°C