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प्रश्न
2000 mmol of an ideal gas expanded isothermally and reversibly from 20 L to 30 L at 300 K, calculate the work done in the process (R = 8.314 JK–1 mol–1).
उत्तर
Given: n = 2000 mmol = 2 mol, V1 = 20 L, V2 = 30 L, T = 300 K, W = ?
Formula: W = `-2.303"nRT" log_10 "V"_2/"V"_1`
∴ W = `-2.303 xx 2 xx 8.314 xx 300 xx log_10 30/20`
∴ W = −2022.98 J
∴ W = −2.023 kJ
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