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प्रश्न
3x + 23x2 + 6y2 + 2x + y2 + ______ = 5x + 7y2.
उत्तर
3x + 23x2 + 6y2 + 2x + y2 + –23x2 = 5x + 7y2.
Explanation:
Let (3x + 23x2 + 6y2 + 2x + y2) + M = 5x + 7y2
⇒ M = (5x + 7y2) – (3x + 23x2 + 6y2 + 2x + y2)
⇒ M = 5x + 7y2 – 3x – 23x2 – 6y2 – 2x – y2 ......[With –ve sign, +ve sign in the bracket will change on opening it]
⇒ M = 5x – 3x – 2x + 7y2 – 6y2 – y2 – 23x2
M = 0 + 0 – 23x2 = –23x2
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संबंधित प्रश्न
Group the like term together: 9x2, xy, – 3x2, x2 and – 2xy
Add : a + b and 2a + 3b
Subtract the second expression from the first:
a3 - 1 + a, 3a - 2a2
Subtract the second expression from the first:
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Simplify: `"p"^2 - ["x"^2 - {"x"^2 - ("q"^2 - bar("x"^2 - "q"^2)) - "2y"^2}]`
Simplify: `"x" - ("3y" - bar"4x - 3x" + 2z - bar"5y - 7x")`
The value of (3x3 + 9x2 + 27x) ÷ 3x is ______.
The factors of a2 – 2ab + b2 are (a + b) and (a + b).
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qrxy, pryz, rxyz
Coefficient of x in –9xy2z is ______.
