Advertisements
Advertisements
Question
3x + 23x2 + 6y2 + 2x + y2 + ______ = 5x + 7y2.
Solution
3x + 23x2 + 6y2 + 2x + y2 + –23x2 = 5x + 7y2.
Explanation:
Let (3x + 23x2 + 6y2 + 2x + y2) + M = 5x + 7y2
⇒ M = (5x + 7y2) – (3x + 23x2 + 6y2 + 2x + y2)
⇒ M = 5x + 7y2 – 3x – 23x2 – 6y2 – 2x – y2 ......[With –ve sign, +ve sign in the bracket will change on opening it]
⇒ M = 5x – 3x – 2x + 7y2 – 6y2 – y2 – 23x2
M = 0 + 0 – 23x2 = –23x2
APPEARS IN
RELATED QUESTIONS
Identify term which contain x and give the coefficient of x.
y2x + y
Identify the term, their coefficients for the following expression:
3x2y2 − 5x2y2z2 + z2
For the following monomials, write its degree: – 9y2z3
Write numerical co-efficient of the following: – 9a2b3
Find the sum of: 9x2 – 6x + 7, 5 – 4x and 6 – 3x2
Simplify: {9 – (4p – 6q)} – {3q – (5p – 10)}
Simplify: 2 [a – 3 {a + 5 {a – 2) + 7}]
Factorise the following expression.
24x2yz3 – 6xy3z2 + 15x2y2z – 5xyz
Factorise the following expression.
a3 + a2 + a + 1
Identify term and factor in the expression given below:
5y + 3y2