Advertisements
Advertisements
प्रश्न
5 chairs and 4 tables together cost ₹5600, while 4 chairs and 3 tables together cost
₹ 4340. Find the cost of each chair and that of each table
उत्तर
Let the cost of a chair be ₹ x and that of a table be ₹ y, then
5x + 4y = 5600 ……..(i)
4x + 3y = 4340 ……..(ii)
Multiplying (i) by 3 and (ii) by 4, we get
15x – 16x = 16800 – 17360
⇒ -x = -560
⇒ x = 560
Substituting x = 560 in (i), we have
5 × 560 + 4y = 5600
⇒ 4y = 5600 – 2800
⇒ y = `2800/4` = 700
Hence, the cost of a chair and that a table are respectively ₹ 560 and ₹ 700.
APPEARS IN
संबंधित प्रश्न
The coach of a cricket team buys 3 bats and 6 balls for Rs 3900. Later, she buys another bat and 3 more balls of the same kind for Rs 1300. Represent this situation algebraically and geometrically.
For what value of α, the system of equations
αx + 3y = α - 3
12x + αy = α
will have no solution?
For what value of k, the following system of equations will represent the coincident lines?
x + 2y + 7 = 0
2x + ky + 14 = 0
Solve for x and y:
`1/(3x+y) + 1/(3x−y) = 3/4, 1/(2(3x+y)) - 1/(2(3x−y)) = −1/8`
Solve for x and y:
`1/(2(x+2y)) + 5/(3(3x−2y)) = - 3/2, 1/(4(x+2y)) - 3/(5(3x−2y)) = 61/60` where x + 2y ≠ 0 and 3x – 2y ≠ 0.
Find the value of k for which the system of equations has a unique solution:
4x + ky + 8=0,
x + y + 1 = 0.
Find a fraction which becomes `(1/2)` when 1 is subtracted from the numerator and 2 is added to the denominator, and the fraction becomes `(1/3)` when 7 is subtracted from the numerator and 2 is subtracted from the denominator.
Write the number of solutions of the following pair of linear equations:
x + 3y – 4 = 0, 2x + 6y – 7 = 0.
A man purchased 47 stamps of 20p and 25p for ₹10. Find the number of each type of stamps
If 217x + 131y = 913, 131x + 217y = 827, then x + y is ______.
