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प्रश्न
A 5% solution of \[\ce{Na2SO4.10H2O}\] (MW = 3 22) is isotonic with 2% solution of non- electrolytic, non volatile substance X. Find out the molecular weight of X.
उत्तर
π1 = π2
iC1RT = C2RT
`(3 xx 5)/322 = 2/"M"`
M = `(2 xx 322)/(3 xx 5)`
M = 42.9 g
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