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A Block of Mass M Slips on a Rough Horizontal Table Under the Action of a Horizontal Force Applied to It. the Coefficient of Friction Between the Block and the Table is μ. - Physics

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प्रश्न

A block of mass m slips on a rough horizontal table under the action of a horizontal force applied to it. The coefficient of friction between the block and the table is μ. The table does not move on the floor. Find the total frictional force applied by the floor on the legs of the table. Do you need the friction coefficient between the table and the floor or the mass of the table?

बेरीज

उत्तर

When a block slips on a rough horizontal table, the maximum frictional force acting on it can be found from the free body diagram (see below).
R = mg

From the free body diagram, 
F − μR = 0
⇒ F = μR = μmg

But the table is at rest, so the frictional force at the legs of the table is also μR. Let this be f, so from the free body diagram
f − μR = 0
⇒ f = μR = μmg

Therefore, the total frictional force on the table by the floor is μmg.

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 6: Friction - Exercise [पृष्ठ ९९]

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एचसी वर्मा Concepts of Physics Vol. 1 [English] Class 11 and 12
पाठ 6 Friction
Exercise | Q 27 | पृष्ठ ९९

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