Question

A block of mass m is pulled by a constant power P placed on a rough horizontal plane. The friction co-efficient between the block and the surface is µ. Maximum velocity of the block will be:

पर्याय

• `(mu"P")/"mg"`

• `(mu"mg")/"P"`

• μmgP

• `"P"/(mu"mg")`

Answer 1

`bb("P"/(mu"mg"))`

Explanation:

P = `vec"F".vec"v"` = constant

When F = μmg,

net force on block becomes zero.

i.e. it has maximum or terminal velocity

∴ P = (μmg)v_max

or v_max = `"P"/(mu"mg")`