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Question
A block of mass m is pulled by a constant power P placed on a rough horizontal plane. The friction co-efficient between the block and the surface is µ. Maximum velocity of the block will be:
Options
`(mu"P")/"mg"`
`(mu"mg")/"P"`
μmgP
`"P"/(mu"mg")`
MCQ
Fill in the Blanks
Solution
`bb("P"/(mu"mg"))`
Explanation:
P = `vec"F".vec"v"` = constant
When F = μmg,
net force on block becomes zero.
i.e. it has maximum or terminal velocity
∴ P = (μmg)vmax
or vmax = `"P"/(mu"mg")`
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Friction
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