Advertisements
Advertisements
प्रश्न
A body of mass 5 kg falls from a height of 10 m to 4 m. Calculate:
The total energy possessed by the body at any instant? (Take g = 10 ms-2).
उत्तर
The total energy possessed by the body at
any instant remains constant for free-fall
It is equal to the sum of P.E. and K.E
∴ At height 10 m , i.e. at top most point K.E = 0
∴ Total energy = P.E. + K.E.
Total energy = 500 + 0 = 500 J
APPEARS IN
संबंधित प्रश्न
State the energy change in the following device while in use:
A loudspeaker
Two toy-cars A and B of masses 500 g and 200 g respectively are moving with the same speed. Which of the two has the greater kinetic energy?
Name the type of energy (kinetic or potential) possessed by the following:
A moving bus.
A ball is made to fall freely from a height. State the kind/ kinds of energy possessed by the ball when it is just in the middle .
A boy of mass m climbs up a staircase of vertical height h.
(a) What is the work done by the boy against the force of gravity?
(b) What would have been the work done if he uses a lift in climbing the same vertical height?
How is the solar energy used to generate electricity in a solar power plant?
What is a solar cell?
What is dissipation of energy?
A body of mass 50 kg has a momentum of 3000 kg−1 ms. Calculate:
(j) the kinetic energy of the body.
(ii) the velocity of the body.
In a hydroelectric power station, 1000 kg of water is allowed to drop through a height of 100 m in 1 sec. If the conversion of potential energy to electric energy is 60%. Calculate the power output. [Take: g = 10m/sec2]
