Advertisements
Advertisements
प्रश्न
A certain current liberated 0.504 gm of hydrogen in 2 hours. How many grams of copper can be liberated by the same current flowing for the same time through copper sulphate solution.
पर्याय
31.75
15.8
7.5
63.5
उत्तर
15.8
Explanation:
m1 = 0.504 g
m2 = ?
e1 = 1.008
e2 = 31.77
`"m"_1/"m"_2 = "e"_1/"e"_2`
∴ m2 = `"m"_1/"e"_1 ⋅"e"_2`
= `(0.504 xx 31.77)/1.008`
= 15.885 g
APPEARS IN
संबंधित प्रश्न
Derive a relation between ΔH and ΔU for a chemical reaction. Draw neat labelled diagram of calomel electrode. Resistance and conductivity of a cell containing 0.001 M KCI solution at 298K are 1500Ω and 1.46x10-4 S.cm-1 respectively.
Construct a labelled diagram for the following cell:
`Zn|Zn^(2+)(1M)||H^+(1M)|H_(2(g,1atm))|Pt`
How many moles of electrons are required for reduction of 2 moles of Zn2+ to Zn?
What is the SI unit tor electrochemical equivalent?
Consider the following diagram in which an electrochemical cell is coupled to an electrolytic cell. What will be the polarity of electrodes ‘A’ and ‘B’ in the electrolytic cell?
Match the terms given in Column I with the items given in Column II.
Column I | Column II |
(i) Λm | (a) intensive property |
(ii) ECell | (b) depends on number of ions/volume |
(iii) K | (c) extensive property |
(iv) ∆rGCell | (d) increases with dilution |
Assertion: Mercury cell does not give steady potential.
Reason: In the cell reaction, ions are not involved in solution.
Calculate the standard EMF ofa cell which involves the following cell reactions
\[\ce{Zn + 2 Ag+ -> Zn^{2+} + 2 Ag}\]
Given that \[\ce{E^{o}_{Zn/Zn^{2+}}}\] = 0.76 volt and \[\ce{E^{o}_{Ag/Ag^{+}}}\] = – 0.80 volt.
Which of the following statements about galvanic cell is incorrect
Given the data at 25°C
Ag + I– → Agl + e–; E° = – 0.152 V
Ag → Ag+ + e–; E° = – 0.800 V
The value of log Ksp for Ag I is :-