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Question
A certain current liberated 0.504 gm of hydrogen in 2 hours. How many grams of copper can be liberated by the same current flowing for the same time through copper sulphate solution.
Options
31.75
15.8
7.5
63.5
Solution
15.8
Explanation:
m1 = 0.504 g
m2 = ?
e1 = 1.008
e2 = 31.77
`"m"_1/"m"_2 = "e"_1/"e"_2`
∴ m2 = `"m"_1/"e"_1 ⋅"e"_2`
= `(0.504 xx 31.77)/1.008`
= 15.885 g
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