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प्रश्न
A coil in the heater consumes power P on passing current. If it is cut into halves and joined in parallel, it will consume power:
पर्याय
P
`"P"/2`
2P
4P
MCQ
उत्तर
4P
Explanation:
Original power consumed, P = `"V"^2/"R"`
When used in parallel
`1/"R"_"P" = 1/"R"_1 + 1/"R"_2 = 1/("R"/2) + 1/("R"/2) = 4/"R"`
RP = `"R"/4`
∴ New power consumed when two halves in parallel
P' = `"V"^2/"R"_"P" = "V"^2/("R"/4) = (4 "V"^2)/"R"` = 4P
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