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A coil in the heater consumes power P on passing current. If it is cut into halves and joined in parallel, it will consume power: -

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Question

A coil in the heater consumes power P on passing current. If it is cut into halves and joined in parallel, it will consume power:

Options

  • P

  • `"P"/2`

  • 2P

  • 4P

MCQ

Solution

4P

Explanation:

Original power consumed, P = `"V"^2/"R"`

When used in parallel

`1/"R"_"P" = 1/"R"_1 + 1/"R"_2 = 1/("R"/2) + 1/("R"/2) = 4/"R"`

RP = `"R"/4`

∴ New power consumed when two halves in parallel

P' = `"V"^2/"R"_"P" = "V"^2/("R"/4) = (4 "V"^2)/"R"` = 4P

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