Advertisements
Advertisements
प्रश्न
A conductor carrying a current I has three segments, as shown in figure. What is the magnetic field B at the centre of curvature C of the semicircle?
पर्याय
`(μ_0I)/(4piR)`
`(μ_0I)/(4R)`
`μ_0/(4pi) I/R^2`
`(μ_0I)/(4R)`
MCQ
उत्तर
`underline((μ_0I)/(4R))`
Explanation:
Magnetic field due to straight portion = 0
Magnetic field due to curved is
`= 1/2((μ_0I)/(2R)) = (μ_0I)/(4R)`
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
