Question

A conductor carrying a current I has three segments, as shown in figure. What is the magnetic field B at the centre of curvature C of the semicircle?

Options

• `(μ_0I)/(4piR)`

• `(μ_0I)/(4R)`

• `μ_0/(4pi) I/R^2`

• `(μ_0I)/(4R)`

Answer 1

`underline((μ_0I)/(4R))`

Explanation:

Magnetic field due to straight portion = 0

Magnetic field due to curved is

`= 1/2((μ_0I)/(2R)) = (μ_0I)/(4R)`