Question

A cooler of 1500 W, 200 volts and a fan of 500 W, 200 volts are to be used from a household supply. The rating of fuse to be used is:

पर्याय

• 2.5 A

• 5.0 A

• 7.5 A

• 10 A

Answer 1

10 A

Explanation:

Total power used, P = P₁ + P₁ = 1500 + 500 = 2000 W.

Current drawn from the supply,

I = `"P"/"V" = 2000/200`

= 10 A