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Question
A cooler of 1500 W, 200 volts and a fan of 500 W, 200 volts are to be used from a household supply. The rating of fuse to be used is:
Options
2.5 A
5.0 A
7.5 A
10 A
MCQ
Solution
10 A
Explanation:
Total power used, P = P1 + P1 = 1500 + 500 = 2000 W.
Current drawn from the supply,
I = `"P"/"V" = 2000/200`
= 10 A
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