Question

A current of 3 A is flowing in a linear conductor having a length of 40 cm. The conductor is placed in a magnetic field of strength of 500 gauss and makes an angle of 30° with the direction of the field. It experiences a force of magnitude:

पर्याय

• 3 × 10⁻⁴ N

• 3 × 10⁻² N

• 3 × 10² N

• 3 × 10⁴ N

Answer 1

3 × 10⁻² N

Explanation:

F = Iℓ B sin θ = 3 × 0.40 × (500 × 10⁻⁴) × sin 30° = 3 × 10⁻² N