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Question
A current of 3 A is flowing in a linear conductor having a length of 40 cm. The conductor is placed in a magnetic field of strength of 500 gauss and makes an angle of 30° with the direction of the field. It experiences a force of magnitude:
Options
3 × 10−4 N
3 × 10−2 N
3 × 102 N
3 × 104 N
MCQ
Solution
3 × 10−2 N
Explanation:
F = Iℓ B sin θ = 3 × 0.40 × (500 × 10−4) × sin 30° = 3 × 10−2 N
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