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प्रश्न
A current of 3 A is passed through a coil of resistance 75 Ω for 2 minutes.
- How much heat energy is produced?
- How much charge is passed through the resistance?
उत्तर
Current (I) = 3 A,
Resistance (R) = 75 Ω
Time (t) = 2 min
= 2 × 60
= 120 sec
- Heat energy w = I2Rt
= 32 × 75 × 120
= 9 × 75 × 120
= 81000 J - Charge Q = I × t
= 3 × 120
= 360 C
संबंधित प्रश्न
A boy noted the reading on his home's electricity meter on Sunday at 8 AM and again on Monday at 8 AM (see Figures below).
(a) What was the meter reading on Sunday?
(b) What was the meter reading on Monday?
(c) How many units of electricity have been used?
(d) In how much time these units have been used?
(e) If the rate is Rs 5 per unit, what is the cost of electricity used during this time?
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Reason (R): The level of the bird is very high from the ground.
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