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Question
A current of 3 A is passed through a coil of resistance 75 Ω for 2 minutes.
- How much heat energy is produced?
- How much charge is passed through the resistance?
Solution
Current (I) = 3 A,
Resistance (R) = 75 Ω
Time (t) = 2 min
= 2 × 60
= 120 sec
- Heat energy w = I2Rt
= 32 × 75 × 120
= 9 × 75 × 120
= 81000 J - Charge Q = I × t
= 3 × 120
= 360 C
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