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A cylinder of radius 12 cm contains water to a depth of 20 cm. A spherical iron ball is dropped into the cylinder and thus the level of water is raised by 6.75 cm. Find the radius of the ball.
(Use ЁЭЬЛ = 22/7).
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Given that,
Radius of cylinder= 12cm =`r_1`
Raised in height =6.75cm=h
⇒ Volume of water raised = Volume of the sphere
⇒ `πr_1^2h=4/3πr_2^3`
⇒ `(12xx12xx6.75)=4/3r_2^3`
⇒`(12xx12xx6.75xx3)/4=r_2^3`
⇒`r_2^3=729`
⇒`r_2=9cm`
Radius of sphere is 9cm.
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