Advertisements
Advertisements
प्रश्न
A family uses a light bulb of 100W, a fan of 100W, and a heater of 1000W, each for 8 hours a day. If the cost of electricity is Rs. 2 per unit, what is the expenditure to the family per day, on electricity?
उत्तर
Power consumed in watt-hours
= 100 × 8 + 100 × 8 + 1000 × 8
(bulb) (fan) (heater)
= (800 + 800 + 8000) watt-hours
= 9600 watt hour (units)
i.e. Electric energy comsumed in kWh (units)
`= 9600/1000 = 9.6` kWh.
Cost at Rs. 2 per unit or per kWh
= Rs. 2 × 9.6 = Rs. 19.20.
APPEARS IN
संबंधित प्रश्न
Define Electric power
Which of the following terms does not represent electrical power in a circuit?
State and define the household unit of electricity.
An electric heater is rated 220 V, 550 W. Electrical energy is also measured in kWh. What do you understand by a kilo-watt-hour?
You are required to connect a bulb, a fan and a socket outlet to the mains in one set A and an air-conditioner and a refrigerator to the mains in other set B. Will you recommend the wire of same thickness and same insulation in both? explain your answer.
An Electric bulb is marked 100 W, 230 V. What find the energy consumed by the bulb in one hour.
Two bulbs are rated: bulb A 100W, 120 V bulb B 10W, 120 V. If both are connected across a 120V supply, which bulb will consume more energy, When in series? Also calculate the current through each bulb in above cases.