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A Family Uses a Light Bulb of 100w, a Fan of 100w, and a Heater of 1000w, Each for 8 Hours a Day. If the Cost of Electricity is Rs. 2 per Unit, - Physics

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Question

A family uses a light bulb of 100W, a fan of 100W, and a heater of 1000W, each for 8 hours a day. If the cost of electricity is Rs. 2 per unit, what is the expenditure to the family per day, on electricity?

Sum

Solution

Power consumed in watt-hours

= 100 × 8 + 100 × 8 + 1000 × 8
      (bulb)         (fan)        (heater)

= (800 + 800 + 8000) watt-hours

= 9600 watt hour (units)

i.e. Electric energy comsumed in kWh (units)

`= 9600/1000 = 9.6` kWh.

Cost at Rs. 2 per unit or per kWh

= Rs. 2 × 9.6 = Rs. 19.20.

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Chapter 8: Electric Power and House hold Circuits - Short Numericals

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ICSE Physics [English] Class 10
Chapter 8 Electric Power and House hold Circuits
Short Numericals | Q 7
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