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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

(a) For the telescope is in normal adjustment (i.e., when the final image is at infinity)? what is the separation between the objective lens and the eyepiece? - Physics

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प्रश्न

  1. For the telescope is in normal adjustment (i.e., when the final image is at infinity)? what is the separation between the objective lens and the eyepiece?
  2. If this telescope is used to view a 100 m tall tower 3 km away, what is the height of the image of the tower formed by the objective lens?
  3. What is the height of the final image of the tower if it is formed at 25 cm?
संख्यात्मक

उत्तर

Focal length of the objective lens, fo = 140 cm

Focal length of the eyepiece, fe = 5 cm

(a) In normal adjustment, the separation between the objective lens and the eyepiece = fo + fe = 140  + 5 = 145 cm

(b) Height of the tower, h1 = 100 m

Distance of the tower (object) from the telescope, u = 3 km = 3000 m

The angle subtended by the tower at the telescope is given as:

θ = `"h"_1/"u"`

= `100/3000`

= `1/30` rad

The angle subtended by the image produced by the objective lens is given as:

θ = `"h"_2/"f"_"o" = "h"_2/140 "rad"`

Where,

h2 = Height of the image of the tower formed by the objective lens

`1/30 = "h"_2/140`

`"h"_2 = 140/30`

∴ h2 = 4.7 cm

Therefore, the objective lens forms a 4.7 cm tall image of the tower.

(c) Image is formed at a distance, d = 25 cm

The magnification of the eyepiece is given by the relation:

`"m" = 1 + "d"/"f"_"e"`

= `1 + 25/5`

= 1 + 5

= 6

Height of the final image = mh2 = 6 × 4.7 = 28.2 cm

Hence, the height of the final image of the tower is 28.2 cm.

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पाठ 9: Ray Optics and Optical Instruments - Exercise [पृष्ठ ३४७]

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संबंधित प्रश्‍न

A small telescope has an objective lens of focal length 140 cm and an eyepiece of focal length 5.0 cm. What is the magnifying power of the telescope for viewing distant objects when

  1. the telescope is in normal adjustment (i.e., when the final image is at infinity)?
  2. the final image is formed at the least distance of distinct vision (25 cm)?

Why should the objective of a telescope have large focal length and large aperture? Justify your answer. 


Draw a ray diagram depicting the formation of the image by an astronomical telescope in normal adjustment.


You are given the following three lenses. Which two lenses will you use as an eyepiece and as an objective to construct an astronomical telescope ? Give reason

Lenses Power (D) Aperture (cm)
L1 3 8
L2 6 1
L3 10 1

You are given three lenses of power 0.5 D, 4 D, and 10 D to design a telescope.

1) Which lenses should be used as objective and eyepiece? Justify your answer.

2) Why is the aperture of the objective preferred to be large?


A giant refracting telescope at an observatory has an objective lens of focal length 15 m. If an eyepiece lens of focal length 1.0 cm is used, find the angular magnification of the telescope. If this telescope is used to view the moon, what is the diameter of the image of the moon formed by the objective lens? The diameter of the moon is 3.42 × 106 m and the radius of the lunar orbit is 3.8 × 108 m.


An astronomical telescope is to be designed to have a magnifying power of 50 in normal adjustment. If the length of the tube is 102 cm, find the powers of the objective and the eyepiece.


The eyepiece of an astronomical telescope has a focal length of 10 cm. The telescope is focussed for normal vision of distant objects when the tube length is 1.0. m. Find the focal length of the objective and the magnifying power of the telescope.


(i) What is meant by resolving power of a telescope?
(ii) State any one method of increasing the resolving power of an astronomical telescope.


Draw a labelled ray diagram of an astronomical telescope in the near point adjustment position. A giant refracting telescope at an observatory has an objective lens of focal length 15 m and an eyepiece of focal length 1.0 cm. If this telescope is used to view the Moon, find the diameter of the image of the Moon formed by the objective lens. The diameter of the Moon is `3.48 xx 10^6`m, and the radius of the lunar orbit is `3.48 xx 10^8`m.


Define the term 'resolving power of a telescope'. How will the resolving power be effected with the increase in
(i) Wavelength of light used.
(ii) Diameter of the objective lens.


A small telescope has an objective lens of focal length 140 cm and an eyepiece of focal length 5.0 cm. Find the magnifying power of the telescope for viewing distant objects when

  1. the telescope is in normal adjustment,
  2. the final image is formed at the least distance of distinct vision.

Read the following paragraph and answer the questions.

A number of optical devices and instruments have been designed and developed such as periscope, binoculars, microscopes and telescopes utilising the reflecting and refracting properties of mirrors, lenses and prisms. Most of them are in common use. Our knowledge about the formation of images by the mirrors and lenses is the basic requirement for understanding the working of these devices.
  1. Why the image formed at infinity is often considered most suitable for viewing. Explain
  2. In modern microscopes, multicomponent lenses are used for both the objective and the eyepiece. Why?
  3. Write two points of difference between a compound microscope and an astronomical telescope
    OR
    Write two distinct advantages of a reflecting type telescope over a refracting type telescope.

With the help of a ray diagram explain the working of a reflecting telescope.


The magnifying power of an astronomical telescope in normal adjustment is 2.9 and the objective and the eyepiece are separated by a distance of 150 cm. Find the focal lengths of the two lenses.


Assertion: An astronomical telescope has an objective lens having large focal length.

Reason: Magnifying power of an astronomical telescope varies directly with focal length of the objective lens.


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