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A Force of 50 N Acts on a Body and Moves It a Distance of 4 M on Horizontal Surface. Calculate the Work Done If the Direction of Force is at an Angle of 60° to the Horizontal Surface. - Science

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प्रश्न

A force of 50 N acts on a body and moves it a distance of 4 m on horizontal surface. Calculate the work done if the direction of force is at an angle of 60° to the horizontal surface.

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उत्तर

 We have a situation in which, work is done by force acting obliquely.
Force, (F) = 50 N
Distance travelled by the body, (S) = 4 m
Angle between force and direction of distance, (θ) = 60°
We have a relation as,
 W = (F)(S) cos θ
So,
`W = (50) (4)  cos 60^circ`
= `200 (1/2)` J
= 100 J
So , the work done is 100 J . 

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पाठ 4: Work and energy - Very Short Answers 1 [पृष्ठ १४७]

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लखमीर सिंह Physics (Science) [English] Class 9 ICSE
पाठ 4 Work and energy
Very Short Answers 1 | Q 54.2 | पृष्ठ १४७

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