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प्रश्न
A function f: [– 5, 9] → R is defined as follow :
f(x) = `{{:(6x + 1";", -5 ≤ x < 2),(5x^2 - 1";", 2 ≤ x < 6),(3x - 4";", 6 ≤ x ≤ 9):}` Find 2f(4) + f(8)
उत्तर
f(x) = 6x + 1; x = {– 5, – 4, – 3, – 2, – 1, 0, 1}
f(x) = 5x2 – 1; x = {2, 3, 4, 5}
f(x) = 3x – 4; x = {6, 7, 8, 9}
2f(4) + f(8)
f(x) = 5x2 – 1
f(4) = 5(4)2 – 1 = 5(16) – 1
= 80 – 1 = 79
f(x) = 3x – 4
f(8) = 3(8) – 4 = 24 – 4 = 20
2f(4) + f(8) = 2(79) + 20
= 158 + 20
= 178
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