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प्रश्न
A gas cylinder contain 12 × 1024 molecules of oxygen gas
If Avogadro's number is 6 × 1023,
calculate :
(i) The mass of oxygen present in the cylinder.
(ii) The volume of oxygen at STP present in the Cylinder[O=16]
उत्तर
1 mole oxygen molecule = 6.022 x 1023 molecules.
19.93 moles of Oxygen molecule = 12 x 1024 molecules
Number moles of O2 = `"Mass of O"_2/"Molar mass of CO"_2`
Mass of O2 = 32 x 19.93 = 637.76g
(ii) 6.022 x 1023 molecules occupies 22.4L
12 x 1024 molecules occupies = `[12 xx 10^24 xx 22.4]/[6.022 xx 10^23]`
= 446.36L volume.
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संबंधित प्रश्न
A gas cylinder contains 12 x 1024 molecules of oxygen gas.
If Avogadro’s number is 6 x 1023; Calculate:
1)The mass of oxygen present in the cylinder.
2) The volume of oxygen at S.T.P. present in the cylinder. [O = 16]
If 150 cc of gas A contains X molecules, how many molecules of gas B will be present in 75 cc of B?. The gases A and B are under the same conditions of temperature and pressure.
Name the law om which same conditions of temperature and pressure
Define atomicity of a gas.
What are the main applications of Avogadro's law?
State : Avogadro's law
Calculate :
The weight of 1022 atoms of carbon [C = 12, Avogadro’s No. = `6xx10^23 ]`
Samples of the gases O2, N2, CO2 and CO under the same conditions of temperature and pressure contain the same number of molecules x. The molecules of oxygen occupy V litres and have a mass of 8 g under the same conditions of temperature and pressure.
What is the volume occupied by:
- x molecules of N2,
- 3x molecules of CO,
- What is the mass of CO2 in grams?
- In answering the above questions, which law have you used?
State the atomicity of Hydrogen.
State the atomicity of Sulphur.
