Advertisements
Advertisements
प्रश्न
उत्तर
We know that,
P=VI= I1R
Given, P = 1200 watt , I= 5A
R = `"P"/"I"^2 = 1200/(5 xx 5) = 48 Omega`
and, V = `"P"/"I" = 1200/5` = 240 V
APPEARS IN
संबंधित प्रश्न
A battery of emf 12 V and internal resistance 2 Ω is connected with two resistors A and B of resistance 4 Ω and 6 Ω respectively joined in series.
Find:
1) Current in the circuit
2) The terminal voltage of the cell
3) The potential difference across 6Ω Resistor
4) Electrical energy spent per minute in the 4Ω resistor.
Which device is used to measure p.d?
What is the ratio of potential difference and current known as?
Write down the formula which states the relation between potential difference, current, and resistance.
The potential difference between the terminals of an electric iron is 240 V and the current is 5.0 A. What is the resistance of the electric iron?
The V-I graph for a series combination and for a parallel combination of two resistors is shown in Fig – 8.38. Which of the two, A or B, represents the parallel combination? Give a reason for your answer.
Define the term ‘volt’.
What is the combined resistance of each of the networks between A and B shown in fig. ?
Which of the following represents voltage?
A current of 1 ampere flows in a series circuit containing an electric lamp and a conductor of 5 Ω when connected to a 10 V battery. Calculate the resistance of the electric lamp.
Now if a resistance of 10 Ω is connected in parallel with this series combination, what change (if any) in current flowing through 5 Ω conductor and potential difference across the lamp will take place? Give reason.
