Advertisements
Advertisements
प्रश्न
A man is thrice as old as his son. After 12 years, he will be twice as old as his son at that time. Find their present ages.
उत्तर
Let the present age of the son = x years
and the present age of the father = 3x years
After 12 years,
Son’s age will be (x + 12) years
and father’s age will be (3x + 12) years
According to the condition,
3x + 12 = 2 (x + 12)
3x + 12 = 2x+ 24
3x – 2x = 24 – 12
x = 12
∴Present age of the son = 12 years
and Present age of the father = 3×12 years
= 36 years
APPEARS IN
संबंधित प्रश्न
Solve the following equation:
`"y"/-12 = - 4`
Solve the following equation:
14 = 27 - x
Solve the following equation:
`"a"/15 - 2 = 0`
Solve the following equation:
2a – 3 =5
8y – 4y = 20
6 = 7 + 2p -5
(x - 4) (2x + 3 ) = 2x²
Solve: `"x"/5 + "2x" = 33`
Six times a number is 72, find the number.
A sum of ₹ 500 is in the form of notes of denominations of ₹ 5 and ₹ 10. If the total number of notes is 90, find the number of notes of each type.
Solve the following equation for the unknown: `(1.5y)/(3) = (7)/(2)`
Solve the following equation for the unknown: `(2"m")/(3) - "m"/(2)` = 1
Solve the following equations for the unknown: `2sqrt((x - 3)/(x + 5)) = (1)/(3)`
Twice a number decreased by 15, equals 25. Find the number.
Divide 300 into two parts so that half of the one part is less than the other by 48.
A man covers a distance of 95 km in 5 hours; partly on foot at the rate of 5 km/h and partly on a motorcycle at 40km/h. Find the distance travelled by him on the motorcycle.
A man went to market at a speed of 4 km/h and returned at a speed of 3km/h. If he took 30 minutes more in returning, find the distance of the market from his home.
The difference between the ages of two brothers is 10 years, and 15 years ago their ages were in the ratio 2:1. Find the ratio of their ages 15 years hence.
How many kilograms of tea at Rs 50 per kg should be mixed with 35 kg of tea costing Rs 60 per kg so as to sell the mixture at Rs 57 per kg without gaining or losing anything in transaction?
