Advertisements
Advertisements
प्रश्न
Divide 300 into two parts so that half of the one part is less than the other by 48.
उत्तर
Let the two parts be x and y.
Then, x + y = 300
Also, one part is less than the other by 48.
⇒ `(1)/(2)(300 - x) - x` = 48
⇒ 300 - 3x = 96
⇒ x = `(204)/(3)` = 68
Then,
y = 300 - 68
= 232.
APPEARS IN
संबंधित प्रश्न
Solve the following equation:
(x – 5)2 – (x + 2)2 = -2
Solve the following equation:
x – 5 = 8
Solve: `"x"/3 - "x"/4 = 2`
Solve: p + 1.4p = 48
Solve: `(2"x" + 1)/("3x" - 2) = 1 1/4`
Solve the following equations for the unknown:
(3x - 1)2 + (4x + 1)2 = (5x + 1)2 + 5
Solve the following equation for the unknown: `-(3.4"m")/(2.7) = (10.2)/(9)`
Shweta's age is six times that of Jayeeta's age. 15 years hence Shweta will be three times as old as Jayeeta; find their ages.
In an isosceles triangle, each of the two equal sides is 4 cm more than the base. If the perimeter of the triangle is 29 cm, find the sides of the triangle.
In a class there are a certain number of seats. If each student occupies one seat, 9 students remain standing and if 2 students occupy one seat, 7 seats are left empty. Find the number of seats in the class.
