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A manufacturer wants to design an open box having a square base and a surface area of 108 sq.cm. Determine the dimensions of the box for the maximum volume - Mathematics

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प्रश्न

A manufacturer wants to design an open box having a square base and a surface area of 108 sq.cm. Determine the dimensions of the box for the maximum volume

बेरीज

उत्तर

Let ‘x’ be the length of the box.

‘y’ be the height of the box.

Given, surface area = 108 sq.cm

i,e. 4(xy) + x2 = 108

⇒ y = `(108 - x^2)/(4x)`

Volume of the box V = x2y

V = `x^2((108 - x^2)/(4x))`

V = `(108x - x^3/4`

`"dV"/("d"x) = (108 - 3x^2)/4`

Maximum or Minimum, 

`"dV"/("d"x)` = 0

⇒ 108 – 3x² = 0

x2 = 36

x = ± 6 [x = – 6 is not possible]

∴ x = 6

Now, `("d"^2"V")/("d"x^2) = - (6x)/4 = - (3x)/2`

At x = 6

`("d"^2"V")/("d"x^2) < 0`

Volume of theboxis maximum when x = 6

y = `(108 - 36)/24`

= `72/24`

= 3

∴ Length of the box = 6 cm

Breadth of the box = 6 cm

Height of the box = 3 cm

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Applications in Optimization
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पाठ 7: Applications of Differential Calculus - Exercise 7.8 [पृष्ठ ४७]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
पाठ 7 Applications of Differential Calculus
Exercise 7.8 | Q 10 | पृष्ठ ४७

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