Advertisements
Advertisements
प्रश्न
A metal ball of heat capacity 50J/°C loses 2000 J of heat. By how much will its temperature fall?
थोडक्यात उत्तर
उत्तर
Heat capacity of ball = 50 J °C-1
Heat lost Q = 200 J
Fall in temperature t =?
Heat Capacity = `"Q"/"t"`
50 = `2000/"t"`
t = `2000/50`
t = 40° C
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
